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Language/Type: C++ array lists arrays
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Author: Marty Stepp (on 2016/06/16)

Write a member function named filter that could be added to the ArrayIntList class. Your function should accept a reference to a Set of integers as its parameter and should remove from your list any integers that appear in the set. Suppose an ArrayIntList variable named list stores the following values:

{3, 14, 5, -1, 7, 14, 7, 7, 29, 3, 7}

And suppose we create a set of integers called set that stores {3, 5, 7}. The call of list.filter(set); would change the list to store the following sequence of four values:

{14, -1, 14, 29}

If the set passed is empty, or if none of its values occur in your list, then the list is unchanged by your function. You should return a result of true if the list is modified and false if it is not modified by the call.

Constraints: You may call other private member functions of the ArrayIntList if you like, but not public ones. Do not make assumptions about how many elements are in the list or about the list's capacity. Do not use any auxiliary data structures to solve this problem (no array, vector, stack, queue, string, etc). Your function should not modify the state of the set that is passed in; its header should be declared in such a way as to promise this to the client. Your solution must run in O(N2) time or better, where N is the number of elements in the list.

Write the member function as it would appear in ArrayIntList.cpp. You do not need to declare the function header that would appear in ArrayIntList.h. Assume that you are adding this method to the ArrayIntList class as defined below:

class ArrayIntList {
    int* elements;   // array storing element data
    int mysize;      // number of elements in the array
    int capacity;    // array's length
    your code goes here;
Type your solution here:

This is a member function problem. Submit a member function that will become part of an existing C++ class. You do not need to write the complete class, just the member function described in the problem.

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