Write a function named `containsBidiPath`

that accepts two parameters: a reference to a `BasicGraph`

, and a reference to a `Vector`

of strings representing vertex names for a path; and returns `true`

if that path is can be traveled in the graph in both directions, or `false`

if not.
In other words, you would return `true`

if every vertex in the path is found in the graph, and where there is an edge between each neighboring pair of vertexes in the path along the way from start to end, and also back from the end to the start.

For example, if your function were passed given the graph below and the path `{A, B, F, G}`

, you would return `true`

because all of those vertexes are part of the graph and you can travel that path from A to G and back from G to A.
If you were passed the same graph and the path `{A, E, F, I}`

, you would return `false`

because that path does not go back from I to A.
If you were passed the path `{A, X, Z, B}`

, you would return `false`

because X and Z are not in the graph.
You may assume that the graph's state is valid, and that the path and its elements are not null.

A <---> B <---> C
| ^ |
| | |
| | |
V V V
E ----> F <---> G
| |
| |
| |
V V
H <---- I

*Constraints:*
You may assume that the graph's state is valid, and that contains no self-edges (e.g. from V1 to V1). You may define private helper functions if so desired, and you may construct auxiliary collections as needed to solve this problem. You should not modify the contents of the graph such as by adding or removing vertexes or edges from the graph, though you may modify the state variables inside individual vertexes/edges such as `visited`

, `cost`

, etc.