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sumUpTo

Language/Type: JavaScript recursion

Write a recursive function named sumUpTo that accepts an integer parameter n, where sumUpTo(n) returns: 1 + 1/2 + 1/3 + 1/4 + ... + 1/n .

For example, the call of sumUpTo(2) should return 1.5. You should return 0.0 if n is 0, and you should throw an exception with the message, "n must be non-negative", if n is less than 0.

Note: Because JavaScript integers are number types, dividing two integers which do not divide evenly returns the decimal value of the result instead of an integer (for example, 1 / 2 results in 0.5, not 0). Use parseInt(a / b) to parse the result into an integer if needed to solve this problem.

Function: Write a JavaScript function as described, not a complete program.

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