Write a function named has_mirror_twice that accepts two arrays of integers
$a1 and $a2 as parameters and returns true
if $a1 contains all the elements of $a2 in reverse order at
least twice (and false otherwise).
For example, if $a2 stores the elements [1, 2, 3] and $a1
stores the elements [6, 3, 2, 1, 4, 1, 3, 2, 1, 5], your function
should return true.
Assume that both arrays passed to your function will have a length of at least 1.
This means that the shortest possible mirror will be of length 1, representing a single
element (which is its own mirror). A sequence that is a palindrome (the same forwards as
backwards) is considered its own mirror and should be included in your computations.
For example, if $a1 is [6, 1, 2, 1, 4, 1, 2, 1, 5]
and $a2 is [1, 2, 1], your function should return true.
The two occurrences of the mirror might overlap, as shown in the fourth sample call below.
The following table shows some calls to your function and their expected results:
| Arrays |
Returned Value |
$a1 = [6, 1, 2, 1, 3, 1, 3, 2, 1, 5];
$a2 = [1, 2]; |
has_mirror_twice($a1, $a2) returns true |
$a3 = [5, 8, 4, 18, 5, 42, 4, 8, 5, 5];
$a4 = [4, 8, 5]; |
has_mirror_twice($a3, $a4) returns false |
$a5 = [6, 3, 42, 18, 12, 5, 3, 42, 3, 42];
$a6 = [42, 3]; |
has_mirror_twice($a5, $a6) returns true |
$a7 = [6, 1, 2, 4, 2, 1, 2, 4, 2, 1, 5];
$a8 = [1, 2, 4, 2, 1]; |
has_mirror_twice($a7, $a8) returns true |
$a9 = [0, 0];
$aa = [0]; |
has_mirror_twice($a9, $aa) returns true |
$ab = [8, 9, 2, 1];
$ac = [5, 7, 1, 2, 9, 8]; |
has_mirror_twice($ab, $ac) returns false |
Do not modify the contents of either array passed to your function as parameters.
